What is expand ((m-1)(n-1))/((m+1)(n+1)) ?

The solution to expand ((m-1)(n-1))/((m+1)(n+1)) is (mn-m-n+1)/(mn+m+n+1)

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expand ((m-1)(n-1))/((m+1)(n+1))

expand

\frac{( m - 1 ) ( n - 1 )}{( m + 1 ) ( n + 1 )}

\frac{mn - m - n + 1}{mn + m + n + 1}

Solution steps

\frac{( m - 1 ) ( n - 1 )}{( m + 1 ) ( n + 1 )}

Expand

(m + 1) (n + 1) : mn + m + n + 1

= \frac{( m - 1 ) ( n - 1 )}{mn + m + n + 1}

Expand

(m - 1) (n - 1) : mn - m - n + 1

= \frac{mn - m - n + 1}{mn + m + n + 1}

(y - β - δχ)^{2}

\frac{7 x + 3}{( x - 4 ) ( x - 2 )}

\frac{( s + 3 )}{s ^{3} ( s - 2 ) ^{2}}

e^{2 (l n (y) + c)}

- 14 + 3 (x + 10 = 7 (2 x + 4) + x)

What is expand ((m-1)(n-1))/((m+1)(n+1)) ?
The solution to expand ((m-1)(n-1))/((m+1)(n+1)) is (mn-m-n+1)/(mn+m+n+1)