What are the solutions to the equation x^2+14x+35=0 ?

The solutions to the equation x^2+14x+35=0 are x=-7+sqrt(14),x=-7-sqrt(14)

Find the zeros of x^2+14x+35=0

The zeros of x^2+14x+35=0 are x=-7+sqrt(14),x=-7-sqrt(14)

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x^{2} + 14 x + 35 = 0

x = - 7 + 14, x = - 7 - 14

Solution steps

x^{2} + 14 x + 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot 35}{2 \cdot 1}

1 4^{2} - 4 \cdot 1 \cdot 35 = 214

x_{1, 2} = \frac{- 14 \pm 2 14}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 14 + 2 14}{2 \cdot 1}, x_{2} = \frac{- 14 - 2 14}{2 \cdot 1}

x = \frac{- 14 + 2 14}{2 \cdot 1} : - 7 + 14

x = \frac{- 14 - 2 14}{2 \cdot 1} : - 7 - 14

The solutions to the quadratic equation are:

x = - 7 + 14, x = - 7 - 14

x^{2} + 12 x y + 36 y^{2}

x - x^{2} = 0

u^{2} + u - 2 = 0

\frac{3 ^{4}}{3 ^{8}}

What are the solutions to the equation x^2+14x+35=0 ?
The solutions to the equation x^2+14x+35=0 are x=-7+sqrt(14),x=-7-sqrt(14)
Find the zeros of x^2+14x+35=0
The zeros of x^2+14x+35=0 are x=-7+sqrt(14),x=-7-sqrt(14)