What is expand-2(2xe^x+x^2e^x) ?

The solution to expand-2(2xe^x+x^2e^x) is -4e^xx-2e^xx^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand-2(2xe^x+x^2e^x)

expand

- 2 (2 x e^{x} + x^{2} e^{x})

- 4 e^{x} x - 2 e^{x} x^{2}

Solution steps

- 2 (2 x e^{x} + x^{2} e^{x})

= - 2 (2 e^{x} x + e^{x} x^{2})

Apply the distributive law:

a (b + c) = ab + a c

a = - 2, b = 2 x e^{x}, c = x^{2} e^{x}

= - 2 \cdot 2 x e^{x} + (- 2) x^{2} e^{x}

Apply minus-plus rules

+ (- a) = - a

= - 2 \cdot 2 e^{x} x - 2 e^{x} x^{2}

Multiply the numbers:

2 \cdot 2 = 4

= - 4 e^{x} x - 2 e^{x} x^{2}

e^{5 x} (5 x - 1)

\frac{d}{d y} ((x) (x + 4))

(2 + x) [H (x - 2) - H [x - 3]]

(d t + 3 t^{4} d w)^{2}

\frac{x ^{2} + x y + y ^{2}}{x y ( x - y )}

What is expand-2(2xe^x+x^2e^x) ?
The solution to expand-2(2xe^x+x^2e^x) is -4e^xx-2e^xx^2