What is the first d/(dy)((x)(x+4)) ?

The first d/(dy)((x)(x+4)) is 2y+4

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d/(dy)((x)(x+4))

\frac{d}{d y} ((y) (y + 4))

2 y + 4

Solution steps

\frac{d}{d y} ((y) (y + 4))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = y, g = y + 4

= \frac{d y}{d y} (y + 4) + \frac{d}{d y} (y + 4) y

\frac{d y}{d y} = 1

\frac{d}{d y} (y + 4) = 1

= 1 \cdot (y + 4) + 1 \cdot y

Simplify

1 \cdot (y + 4) + 1 \cdot y : 2 y + 4

= 2 y + 4

(2 + x) [H (x - 2) - H [x - 3]]

(d t + 3 t^{4} d w)^{2}

\frac{x ^{2} + x y + y ^{2}}{x y ( x - y )}

\frac{( 5 - 2 x ) ^{2}}{π} - x^{2}

(l, m, n) (1, - 4, - 2)