What are the solutions to the equation -13x^2-x+6=0 ?

The solutions to the equation -13x^2-x+6=0 are x=-(1+sqrt(313))/(26),x=(sqrt(313)-1)/(26)

Find the zeros of -13x^2-x+6=0

The zeros of -13x^2-x+6=0 are x=-(1+sqrt(313))/(26),x=(sqrt(313)-1)/(26)

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- 13 x^{2} - x + 6 = 0

x = - \frac{1 + 313}{26}, x = \frac{313 - 1}{26}

Decimal Notation

x = - 0.71891 \dots, x = 0.64199 \dots

Solution steps

- 13 x^{2} - x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 ( - 13 ) \cdot 6}{2 ( - 13 )}

(- 1)^{2} - 4 (- 13) \cdot 6 = 313

x_{1, 2} = \frac{- ( - 1 ) \pm 313}{2 ( - 13 )}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 313}{2 ( - 13 )}, x_{2} = \frac{- ( - 1 ) - 313}{2 ( - 13 )}

x = \frac{- ( - 1 ) + 313}{2 ( - 13 )} : - \frac{1 + 313}{26}

x = \frac{- ( - 1 ) - 313}{2 ( - 13 )} : \frac{313 - 1}{26}

The solutions to the quadratic equation are:

x = - \frac{1 + 313}{26}, x = \frac{313 - 1}{26}

3 - 11 x = - 118

∣ x + 7 ∣ = 12

x - 2 = 4

16 x^{2} - 400 = 0

y^{- 5} (2 x \frac{y}{\frac{x}{3 y ^{2}}})

What are the solutions to the equation -13x^2-x+6=0 ?
The solutions to the equation -13x^2-x+6=0 are x=-(1+sqrt(313))/(26),x=(sqrt(313)-1)/(26)
Find the zeros of -13x^2-x+6=0
The zeros of -13x^2-x+6=0 are x=-(1+sqrt(313))/(26),x=(sqrt(313)-1)/(26)