What are the solutions to the equation 16x^2-400=0 ?

The solutions to the equation 16x^2-400=0 are x=5,x=-5

Find the zeros of 16x^2-400=0

The zeros of 16x^2-400=0 are x=5,x=-5

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16 x^{2} - 400 = 0

x = 5, x = - 5

Solution steps

16 x^{2} - 400 = 0

Move

400

to the right side

16 x^{2} = 400

Divide both sides by

16

x^{2} = 25

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 25, x = - 25

25 = 5

- 25 = - 5

x = 5, x = - 5

y^{- 5} (2 x \frac{y}{\frac{x}{3 y ^{2}}})

\frac{c}{4} = 16

∣ 15 x ∣ \leq 0

2 x = 7 - x^{2}

x^{3} - 2 x^{2} - 5 x + 6

What are the solutions to the equation 16x^2-400=0 ?
The solutions to the equation 16x^2-400=0 are x=5,x=-5
Find the zeros of 16x^2-400=0
The zeros of 16x^2-400=0 are x=5,x=-5