simplify e^{3(3+i)}

Solution

simplify

e^{3 (3 + i)}

e^{9} cos (3) + e^{9} i sin (3)

Solution steps

e^{3 (3 + i)}

Apply imaginary number rule:

e^{a + ib} = e^{a} (cos (b) + i sin (b))

= e^{9} (cos (3) + i sin (3))

Rewrite

e^{9} (cos (3) + sin (3) i)

in standard complex form:

e^{9} cos (3) + e^{9} sin (3) i

= e^{9} cos (3) + e^{9} sin (3) i

\frac{ln ( 4 + x ^{2} )}{( 1 + x ) ^{2}}

- 2 e^{2 x} (e^{- 2 x} + 1)^{2}

(x^{3} - 2 x^{2} - 5 x) (x - 1)^{'}

(1, - 2, 0) X (2, 1, 0)

[- (x - 6)]^{2}