What is expand (dn)/((dan+1)(dan)) ?

The solution to expand (dn)/((dan+1)(dan)) is (dn)/(n^2da^2+nda)

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expand (dn)/((dan+1)(dan))

expand

\frac{d n}{( d an + 1 ) ( d an )}

\frac{d n}{n ^{2} d a ^{2} + n d a}

Solution steps

\frac{d n}{( d an + 1 ) ( d an )}

Remove parentheses:

(a) = a

= \frac{d n}{( d an + 1 ) d an}

Expand

(d an + 1) d an : n^{2} d a^{2} + n d a

= \frac{d n}{n ^{2} d a ^{2} + n d a}

\frac{( 1 - x ) ^{2}}{x ^{2} + 1}

\frac{( 8 x - 1 ) ( 2 x + 3 )}{4}

\frac{x}{( 1 + e ^{- x} ) ^{2}}

\frac{9 π ( - 2 ln ( 3 ) - 1 )}{40}

x ((x - 4) (x - 3)) ((x - 2) (x - 1))

What is expand (dn)/((dan+1)(dan)) ?
The solution to expand (dn)/((dan+1)(dan)) is (dn)/(n^2da^2+nda)