What is expand (4+3i)'*(3+2i) ?

The solution to expand (4+3i)'*(3+2i) is 3(4+3i)'+2i(4+3i)'

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (4+3i)'*(3+2i)

expand

(4 + 3 i)^{'} \cdot (3 + 2 i)

3 (4 + 3 i)' + 2 i (4 + 3 i)'

Solution steps

(4 + 3 i)^{'} (3 + 2 i)

= (3 + 2 i) (4 + 3 i)^{^{'}}

Apply the distributive law:

a (b + c) = ab + a c

a = (4 + 3 i)^{'}, b = 3, c = 2 i

= (4 + 3 i)^{^{'}} 3 + (4 + 3 i)^{^{'}} 2 i

= 3 (4 + 3 i)^{^{'}} + 2 i (4 + 3 i)^{^{'}}

- \frac{( 1 - x ^{2} ) ^{4}}{4}

(10 x + 4) d x

\frac{X ( 1 - X ) ^{3}}{3}

133 \cdot 24

- \frac{( t ^{2} + t ) x + 6 x}{2}

What is expand (4+3i)'*(3+2i) ?
The solution to expand (4+3i)'*(3+2i) is 3(4+3i)'+2i(4+3i)'