What is the first d/(dq)((c)(2q+75)) ?

The first d/(dq)((c)(2q+75)) is 2c

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

d/(dq)((c)(2q+75))

\frac{d}{d q} ((c) (2 q + 75))

2 c

Solution steps

\frac{d}{d q} ((c) (2 q + 75))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= c \frac{d}{d q} (2 q + 75)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= c (\frac{d}{d q} (2 q) + \frac{d}{d q} (75))

\frac{d}{d q} (2 q) = 2

\frac{d}{d q} (75) = 0

= c (2 + 0)

Simplify

= 2 c

(- \frac{3 ( x - 2 )}{x + 1}) - 1

\frac{10 x}{( x + 1 ) ^{2}}

\frac{( x + 2 ) ( x - 1 )}{( x - 4 ) ( x + 3 )}

(3 x + 5 y = 3, 3) (12 x - 7 y = 51)

ln (q) (- \frac{1}{a} - 1)