What is expand-2(5x+3y=21) ?

The solution to expand-2(5x+3y=21) is -10x-6y=21

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expand-2(5x+3y=21)

expand

- 2 (5 x + 3 y = 21)

- 10 x - 6 y = 21

Solution steps

- 2 (5 x + 3 y = 21)

= - 2 (5 x + 3 \cdot 21 = y)

Apply the distributive law:

a (b + c) = ab + a c

a = - 2, b = 5 x, c = 3 y = 21

- 2 \cdot 5 x + (- 2) \cdot 3 y = 21

Apply minus-plus rules

+ (- a) = - a

- 2 \cdot 5 x - 2 \cdot 3 y = 21

Expand

- 2 \cdot 5 x - 2 \cdot 3 y : - 10 x - 6 y

- 10 x - 6 y = 21

ln (q) (- \frac{1}{a} - 1) - ln (- a)

\frac{20 ( 41 - 2 x )}{3}

(x - 3) (x + 1) \circ (6 x - 2)

\frac{1}{z ( 1 + z )}

- \frac{( x + 7 ) ( x - 4 )}{18}