What is expand (x-3)(x+1)\circ (6x-2) ?

The solution to expand (x-3)(x+1)\circ (6x-2) is 6\circ x^3-14\circ x^2-14\circ x+6\circ

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expand (x-3)(x+1)\circ (6x-2)

expand

(x - 3) (x + 1) \circ (6 x - 2)

6 \circ x^{3} - 14 \circ x^{2} - 14 \circ x + 6 \circ

Solution steps

(x - 3) (x + 1) \circ (6 x - 2)

= \circ (x - 3) (x + 1) (6 x - 2)

Expand

(x - 3) (x + 1) : x^{2} - 2 x - 3

= \circ (x^{2} - 2 x - 3) (6 x - 2)

Expand

(x^{2} - 2 x - 3) (6 x - 2) : 6 x^{3} - 14 x^{2} - 14 x + 6

= \circ (6 x^{3} - 14 x^{2} - 14 x + 6)

Expand

\circ (6 x^{3} - 14 x^{2} - 14 x + 6) : 6 \circ x^{3} - 14 \circ x^{2} - 14 \circ x + 6 \circ

= 6 \circ x^{3} - 14 \circ x^{2} - 14 \circ x + 6 \circ

\frac{1}{z ( 1 + z )}

- \frac{( x + 7 ) ( x - 4 )}{18}

\frac{( x + 1 ) ^{2}}{3 x ^{4}}

\frac{63}{( x + 8 ) x}

\frac{4 x}{( - x + 1 ) ( x + 1 )}

What is expand (x-3)(x+1)\circ (6x-2) ?
The solution to expand (x-3)(x+1)\circ (6x-2) is 6\circ x^3-14\circ x^2-14\circ x+6\circ