What is expand (x+6)/((x-3)(x-4)) ?

The solution to expand (x+6)/((x-3)(x-4)) is (x+6)/(x^2-7x+12)

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expand (x+6)/((x-3)(x-4))

expand

\frac{x + 6}{( x - 3 ) ( x - 4 )}

\frac{x + 6}{x ^{2} - 7 x + 12}

Solution steps

\frac{x + 6}{( x - 3 ) ( x - 4 )}

Expand

(x - 3) (x - 4) : x^{2} - 7 x + 12

= \frac{x + 6}{x ^{2} - 7 x + 12}

\frac{4}{( s + 1 ) ( s + 3 ) s}

A (- 2, 2) y B (3, - 4)

\frac{f ( 14 + h ) - 14}{h}

e^{t} (- e^{- t} t - e^{- t} + C)

(4, - 10) y (7, r)

What is expand (x+6)/((x-3)(x-4)) ?
The solution to expand (x+6)/((x-3)(x-4)) is (x+6)/(x^2-7x+12)