What is expand (-12-3^'i)^2 ?

The solution to expand (-12-3^'i)^2 is (144-9^')+24*3^'i

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expand (-12-3^'i)^2

expand

(- 12 - 3^{^{'}} i)^{2}

(144 - 9^{'}) + 24 \cdot 3^{'} i

Solution steps

(- 12 - 3^{^{'}} i)^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

a = - 12, b = 3^{^{'}} i

= (- 12)^{2} - 2 (- 12) \cdot 3^{^{^{'}}} i + (3^{^{^{'}}} i)^{2}

Simplify

(- 12)^{2} - 2 (- 12) \cdot 3^{^{'}} i + (3^{^{'}} i)^{2} : 144 + 24 \cdot 3^{^{'}} i - 9^{^{'}}

= 144 + 24 \cdot 3^{^{'}} i - 9^{^{'}}

Rewrite

144 + 24 \cdot 3^{^{'}} i - 9^{^{'}}

in standard complex form:

(144 - 9^{^{'}}) + 24 \cdot 3^{^{'}} i

= (144 - 9^{^{^{'}}}) + 24 \cdot 3^{^{^{'}}} i

2 x y^{3} i^{+} (1 + 3 x^{2} y^{2}) j

- \frac{4}{9} (2 z - 3 = 1)

a (- 1, - 1) b (- 1, 2) c (3, - 1)

\frac{( 2 x - 5 ) ( x + 3 )}{x - 2}

(x^{2} + 4 x + 3 \circ x + 1) (3)

What is expand (-12-3^'i)^2 ?
The solution to expand (-12-3^'i)^2 is (144-9^')+24*3^'i