What is expand ((40x+1)(40x-1))/(25) ?

The solution to expand ((40x+1)(40x-1))/(25) is 64x^2-1/25

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expand ((40x+1)(40x-1))/(25)

expand

\frac{( 40 x + 1 ) ( 40 x - 1 )}{25}

64 x^{2} - \frac{1}{25}

Solution steps

\frac{( 40 x + 1 ) ( 40 x - 1 )}{25}

Expand

(40 x + 1) (40 x - 1) : 1600 x^{2} - 1

= \frac{1600 x ^{2} - 1}{25}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{1600 x ^{2} - 1}{25} = \frac{1600 x ^{2}}{25} - \frac{1}{25}

= \frac{1600 x ^{2}}{25} - \frac{1}{25}

Divide the numbers:

\frac{1600}{25} = 64

= 64 x^{2} - \frac{1}{25}

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What is expand ((40x+1)(40x-1))/(25) ?
The solution to expand ((40x+1)(40x-1))/(25) is 64x^2-1/25