What is expand (8x^2-2xy+3)(dx)/(dy) ?

The solution to expand (8x^2-2xy+3)(dx)/(dy) is 8x^2(dx)/(dy)-2xy(dx)/(dy)+3(dx)/(dy)

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expand (8x^2-2xy+3)(dx)/(dy)

expand

(8 x^{2} - 2 x y + 3) \frac{d x}{d y}

8 x^{2} \frac{d x}{d y} - 2 x y \frac{d x}{d y} + 3 \frac{d x}{d y}

Solution steps

(8 x^{2} - 2 x y + 3) \frac{d x}{d y}

Distribute parentheses

= \frac{d x}{d y} 8 x^{2} + \frac{d x}{d y} (- 2 x y) + \frac{d x}{d y} 3

Apply minus-plus rules

+ (- a) = - a

= 8 x^{2} \frac{d x}{d y} - 2 x y \frac{d x}{d y} + 3 \frac{d x}{d y}

- (- 2 x^{2} + 3 x - 7 = 0)

14 a + 18 a

3 t^{2} - 5 t + 6 + 8 t^{2} + 7 t - 9

\frac{1}{( x ^{2} - 1 ) ( x + 2 ) ( 2 x + 1 )}

What is expand (8x^2-2xy+3)(dx)/(dy) ?
The solution to expand (8x^2-2xy+3)(dx)/(dy) is 8x^2(dx)/(dy)-2xy(dx)/(dy)+3(dx)/(dy)