What is expand ((n-2)(n-3))/((n+2)(n+1)) ?

The solution to expand ((n-2)(n-3))/((n+2)(n+1)) is (n^2-5n+6)/(n^2+3n+2)

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expand ((n-2)(n-3))/((n+2)(n+1))

expand

\frac{( n - 2 ) ( n - 3 )}{( n + 2 ) ( n + 1 )}

\frac{n ^{2} - 5 n + 6}{n ^{2} + 3 n + 2}

Solution steps

\frac{( n - 2 ) ( n - 3 )}{( n + 2 ) ( n + 1 )}

Expand

(n + 2) (n + 1) : n^{2} + 3 n + 2

= \frac{( n - 2 ) ( n - 3 )}{n ^{2} + 3 n + 2}

Expand

(n - 2) (n - 3) : n^{2} - 5 n + 6

= \frac{n ^{2} - 5 n + 6}{n ^{2} + 3 n + 2}

e^{2 - t} u (t - 2)

\frac{1}{x ( x - 1 ) ( x + 1 )}

\frac{( n + i ) ^{2}}{n ^{2}}

df (u^{2} + ln (v) - w^{2})

(2 - t) (H (t - 1) - H (t - 2))

What is expand ((n-2)(n-3))/((n+2)(n+1)) ?
The solution to expand ((n-2)(n-3))/((n+2)(n+1)) is (n^2-5n+6)/(n^2+3n+2)