What is expand ((1-3x)(1+3x))/(9x^2) ?

The solution to expand ((1-3x)(1+3x))/(9x^2) is 1/(9x^2)-1

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expand ((1-3x)(1+3x))/(9x^2)

expand

\frac{( 1 - 3 x ) ( 1 + 3 x )}{9 x ^{2}}

\frac{1}{9 x ^{2}} - 1

Solution steps

\frac{( 1 - 3 x ) ( 1 + 3 x )}{9 x ^{2}}

Expand

(1 - 3 x) (1 + 3 x) : 1 - 9 x^{2}

= \frac{1 - 9 x ^{2}}{9 x ^{2}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{1 - 9 x ^{2}}{9 x ^{2}} = \frac{1}{9 x ^{2}} - \frac{9 x ^{2}}{9 x ^{2}}

= \frac{1}{9 x ^{2}} - \frac{9 x ^{2}}{9 x ^{2}}

Apply rule

\frac{a}{a} = 1

\frac{9 x ^{2}}{9 x ^{2}} = 1

= \frac{1}{9 x ^{2}} - 1

d (\frac{f ( x )}{w ( t - 1 )})

\frac{1}{( s - j + 1 ) ( s + j + 1 )}

11 (π + 2)

\frac{x ^{2}}{( x + 4 ) ^{3}}

lo g_{10} (2) (2 x (x - 16))

What is expand ((1-3x)(1+3x))/(9x^2) ?
The solution to expand ((1-3x)(1+3x))/(9x^2) is 1/(9x^2)-1