What is expand 1/((s-j+1)(s+j+1)) ?

The solution to expand 1/((s-j+1)(s+j+1)) is 1/(s^2+2s-j^2+1)

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expand 1/((s-j+1)(s+j+1))

expand

\frac{1}{( s - j + 1 ) ( s + j + 1 )}

\frac{1}{s ^{2} + 2 s - j ^{2} + 1}

Solution steps

\frac{1}{( s - j + 1 ) ( s + j + 1 )}

Expand

(s - j + 1) (s + j + 1) : s^{2} + 2 s - j^{2} + 1

= \frac{1}{s ^{2} + 2 s - j ^{2} + 1}

11 (π + 2)

\frac{x ^{2}}{( x + 4 ) ^{3}}

lo g_{10} (2) (2 x (x - 16))

2 e (x - 1)

\frac{d}{d y} ((x) (x^{2} - 2 x y))

What is expand 1/((s-j+1)(s+j+1)) ?
The solution to expand 1/((s-j+1)(s+j+1)) is 1/(s^2+2s-j^2+1)