What is (-2x^2-20x-50)/(x^2+4)>= 0 ?

The solution to (-2x^2-20x-50)/(x^2+4)>= 0 is x=-5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(-2x^2-20x-50)/(x^2+4)>= 0

\frac{- 2 x ^{2} - 20 x - 50}{x ^{2} + 4} \geq 0

x = - 5

Interval Notation

x = - 5

Solution steps

\frac{- 2 x ^{2} - 20 x - 50}{x ^{2} + 4} \geq 0

Factor

\frac{- 2 x ^{2} - 20 x - 50}{x ^{2} + 4} : \frac{- 2 ( x + 5 ) ^{2}}{x ^{2} + 4}

\frac{- 2 ( x + 5 ) ^{2}}{x ^{2} + 4} \geq 0

Multiply both sides by

- 1

(reverse the inequality)

\frac{( - 2 ( x + 5 ) ^{2} ) ( - 1 )}{x ^{2} + 4} \leq 0 \cdot (- 1)

Simplify

\frac{2 ( x + 5 ) ^{2}}{x ^{2} + 4} \leq 0

Divide both sides by

2

\frac{\frac{2 ( x + 5 ) ^{2}}{x ^{2} + 4}}{2} \leq \frac{0}{2}

Simplify

\frac{( x + 5 ) ^{2}}{x ^{2} + 4} \leq 0

Identify the intervals

x = - 5

6 x^{2} - 9 x = - 1

3 x^{2} - 26 x + 35 = 0

- - 36

3 (x - 2) 2 - 37 = 20

(\frac{g ^{3}}{h ^{2}})^{5}

What is (-2x^2-20x-50)/(x^2+4)>= 0 ?
The solution to (-2x^2-20x-50)/(x^2+4)>= 0 is x=-5