What are the solutions to the equation m^2+4=0 ?

The solutions to the equation m^2+4=0 are m=2i,m=-2i

Find the zeros of m^2+4=0

The zeros of m^2+4=0 are m=2i,m=-2i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

m^{2} + 4 = 0

m = 2 i, m = - 2 i

Solution steps

m^{2} + 4 = 0

Move

4

to the right side

m^{2} = - 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

m = - 4, m = - - 4

- 4 = 2 i

- - 4 = - 2 i

m = 2 i, m = - 2 i

4 x^{2} - 25 x + 6 = 0

x^{2} - 14 x + 85 = 0

\frac{( 2 x - 7 )}{4} \leq \frac{1}{3}

16 x y^{2} + 28 x y + 8 y

x^{2} + 12 x = - 32

What are the solutions to the equation m^2+4=0 ?
The solutions to the equation m^2+4=0 are m=2i,m=-2i
Find the zeros of m^2+4=0
The zeros of m^2+4=0 are m=2i,m=-2i