What are the solutions to the equation x^2+8x-46=0 ?

The solutions to the equation x^2+8x-46=0 are x=-4+sqrt(62),x=-4-sqrt(62)

Find the zeros of x^2+8x-46=0

The zeros of x^2+8x-46=0 are x=-4+sqrt(62),x=-4-sqrt(62)

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x^{2} + 8 x - 46 = 0

x = - 4 + 62, x = - 4 - 62

Decimal Notation

x = 3.87400 \dots, x = - 11.87400 \dots

Solution steps

x^{2} + 8 x - 46 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 46 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 46) = 262

x_{1, 2} = \frac{- 8 \pm 2 62}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 2 62}{2 \cdot 1}, x_{2} = \frac{- 8 - 2 62}{2 \cdot 1}

x = \frac{- 8 + 2 62}{2 \cdot 1} : - 4 + 62

x = \frac{- 8 - 2 62}{2 \cdot 1} : - 4 - 62

The solutions to the quadratic equation are:

x = - 4 + 62, x = - 4 - 62

f (x) = (\frac{5}{5 ^{x}})^{\frac{1}{( 1 - x )}}

\frac{( u ^{- 1} v ^{2} ) ^{2}}{( u ^{3} v ^{- 2} ) ^{3}}

0 \cdot x = 0

- π > - 3

3 x^{2} + 2 = 0

What are the solutions to the equation x^2+8x-46=0 ?
The solutions to the equation x^2+8x-46=0 are x=-4+sqrt(62),x=-4-sqrt(62)
Find the zeros of x^2+8x-46=0
The zeros of x^2+8x-46=0 are x=-4+sqrt(62),x=-4-sqrt(62)