What is (ln(80)-ln(10))/(-0.004) ?

The solution to (ln(80)-ln(10))/(-0.004) is -(3ln(2))/(0.004)

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simplify (ln(80)-ln(10))/(-0.004)

simplify

\frac{ln ( 80 ) - ln ( 10 )}{- 0.004}

- \frac{3 ln ( 2 )}{0.004}

Solution steps

\frac{ln ( 80 ) - ln ( 10 )}{- 0.004}

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln (80) - ln (10) = ln (\frac{80}{10})

= \frac{ln ( \frac{80}{10} )}{- 0.004}

Divide the numbers:

\frac{80}{10} = 8

= \frac{ln ( 8 )}{- 0.004}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{ln ( 8 )}{0.004}

Simplify

ln (8) : 3 ln (2)

= - \frac{3 ln ( 2 )}{0.004}

- 3 lo g_{2} (x) - 2 lo g_{2} (y)

ln (\frac{1}{2}) + ln (1)

ln (\frac{1}{298})

ln (\frac{968.3}{896.5})

\frac{1}{3} lo g_{10} (245)

What is (ln(80)-ln(10))/(-0.004) ?
The solution to (ln(80)-ln(10))/(-0.004) is -(3ln(2))/(0.004)