What are the solutions to the equation (x+7)(x-7)=-3x ?

The solutions to the equation (x+7)(x-7)=-3x are x=(-3+sqrt(205))/2 ,x=(-3-sqrt(205))/2

Find the zeros of (x+7)(x-7)=-3x

The zeros of (x+7)(x-7)=-3x are x=(-3+sqrt(205))/2 ,x=(-3-sqrt(205))/2

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(x + 7) (x - 7) = - 3 x

x = \frac{- 3 + 205}{2}, x = \frac{- 3 - 205}{2}

Solution steps

(x + 7) (x - 7) = - 3 x

Expand

(x + 7) (x - 7) : x^{2} - 49

x^{2} - 49 = - 3 x

Move

3 x

to the left side

x^{2} - 49 + 3 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 3 x - 49 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 49 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 49) = 205

x_{1, 2} = \frac{- 3 \pm 205}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 205}{2 \cdot 1}, x_{2} = \frac{- 3 - 205}{2 \cdot 1}

x = \frac{- 3 + 205}{2 \cdot 1} : \frac{- 3 + 205}{2}

x = \frac{- 3 - 205}{2 \cdot 1} : \frac{- 3 - 205}{2}

The solutions to the quadratic equation are:

x = \frac{- 3 + 205}{2}, x = \frac{- 3 - 205}{2}

196 x^{2} - 196 x + 449 = 0

2 x + 1 = 8 x^{2}

x^{2} - 6 x + 1 = 161

35 x^{2} - 26 x - 16 = 0

x = - x^{2} + 30

What are the solutions to the equation (x+7)(x-7)=-3x ?
The solutions to the equation (x+7)(x-7)=-3x are x=(-3+sqrt(205))/2 ,x=(-3-sqrt(205))/2
Find the zeros of (x+7)(x-7)=-3x
The zeros of (x+7)(x-7)=-3x are x=(-3+sqrt(205))/2 ,x=(-3-sqrt(205))/2