What are the solutions to the equation (2x+7)(x-1)=0 ?

The solutions to the equation (2x+7)(x-1)=0 are x=-7/2 ,x=1

Find the zeros of (2x+7)(x-1)=0

The zeros of (2x+7)(x-1)=0 are x=-7/2 ,x=1

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(2 x + 7) (x - 1) = 0

x = - \frac{7}{2}, x = 1

Solution steps

(2 x + 7) (x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x + 7 = 0 or x - 1 = 0

Solve

2 x + 7 = 0 : x = - \frac{7}{2}

Solve

x - 1 = 0 : x = 1

The solutions to the quadratic equation are:

x = - \frac{7}{2}, x = 1

(x + 7) (x - 7) = - 3 x

196 x^{2} - 196 x + 449 = 0

2 x + 1 = 8 x^{2}

x^{2} - 6 x + 1 = 161

35 x^{2} - 26 x - 16 = 0

What are the solutions to the equation (2x+7)(x-1)=0 ?
The solutions to the equation (2x+7)(x-1)=0 are x=-7/2 ,x=1
Find the zeros of (2x+7)(x-1)=0
The zeros of (2x+7)(x-1)=0 are x=-7/2 ,x=1