What are the solutions to the equation x^2-6x+1=161 ?

The solutions to the equation x^2-6x+1=161 are x=16,x=-10

Find the zeros of x^2-6x+1=161

The zeros of x^2-6x+1=161 are x=16,x=-10

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x^{2} - 6 x + 1 = 161

x = 16, x = - 10

Solution steps

x^{2} - 6 x + 1 = 161

Move

161

to the left side

x^{2} - 6 x - 160 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 160 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 160) = 26

x_{1, 2} = \frac{- ( - 6 ) \pm 26}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 26}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 26}{2 \cdot 1}

x = \frac{- ( - 6 ) + 26}{2 \cdot 1} : 16

x = \frac{- ( - 6 ) - 26}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

x = 16, x = - 10

35 x^{2} - 26 x - 16 = 0

x = - x^{2} + 30

16 x^{2} = 34 x - 15

576 x^{2} - 144 x + 25 = 0

50 x^{2} - 50 x + 13 = 0

What are the solutions to the equation x^2-6x+1=161 ?
The solutions to the equation x^2-6x+1=161 are x=16,x=-10
Find the zeros of x^2-6x+1=161
The zeros of x^2-6x+1=161 are x=16,x=-10