What are the solutions to the equation -4+16x-15x^2=0 ?

The solutions to the equation -4+16x-15x^2=0 are x= 2/5 ,x= 2/3

Find the zeros of -4+16x-15x^2=0

The zeros of -4+16x-15x^2=0 are x= 2/5 ,x= 2/3

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- 4 + 16 x - 15 x^{2} = 0

x = \frac{2}{5}, x = \frac{2}{3}

Solution steps

- 4 + 16 x - 15 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 15 x^{2} + 16 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 ( - 15 ) ( - 4 )}{2 ( - 15 )}

1 6^{2} - 4 (- 15) (- 4) = 4

x_{1, 2} = \frac{- 16 \pm 4}{2 ( - 15 )}

Separate the solutions

x_{1} = \frac{- 16 + 4}{2 ( - 15 )}, x_{2} = \frac{- 16 - 4}{2 ( - 15 )}

x = \frac{- 16 + 4}{2 ( - 15 )} : \frac{2}{5}

x = \frac{- 16 - 4}{2 ( - 15 )} : \frac{2}{3}

The solutions to the quadratic equation are:

x = \frac{2}{5}, x = \frac{2}{3}

4 x^{2} - 20 x + 29 = 0

(x + 5)^{2} + 5 (2 x + 3) = 2 (x + 4)^{2}

4 x^{2} + 40 x + 100 = 0

x^{2} - 8 x + 96 = 0

x, 3 x^{2} - 5 y^{6} = 2 x

What are the solutions to the equation -4+16x-15x^2=0 ?
The solutions to the equation -4+16x-15x^2=0 are x= 2/5 ,x= 2/3
Find the zeros of -4+16x-15x^2=0
The zeros of -4+16x-15x^2=0 are x= 2/5 ,x= 2/3