What are the solutions to the equation x^2-8x+96=0 ?

The solutions to the equation x^2-8x+96=0 are x=4+4sqrt(5)i,x=4-4sqrt(5)i

Find the zeros of x^2-8x+96=0

The zeros of x^2-8x+96=0 are x=4+4sqrt(5)i,x=4-4sqrt(5)i

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x^{2} - 8 x + 96 = 0

x = 4 + 45 i, x = 4 - 45 i

Solution steps

x^{2} - 8 x + 96 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 96}{2 \cdot 1}

Simplify

(- 8)^{2} - 4 \cdot 1 \cdot 96 : 85 i

x_{1, 2} = \frac{- ( - 8 ) \pm 8 5 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 8 5 i}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 8 5 i}{2 \cdot 1}

x = \frac{- ( - 8 ) + 8 5 i}{2 \cdot 1} : 4 + 45 i

x = \frac{- ( - 8 ) - 8 5 i}{2 \cdot 1} : 4 - 45 i

The solutions to the quadratic equation are:

x = 4 + 45 i, x = 4 - 45 i

x, 3 x^{2} - 5 y^{6} = 2 x

2 (3 x + 1)^{2} - 8 = 0

9 x^{2} - 18 x + 3 = 0

- x^{2} + 4 x - 96 = 0

2 (5 x + 2)^{2} = 64

What are the solutions to the equation x^2-8x+96=0 ?
The solutions to the equation x^2-8x+96=0 are x=4+4sqrt(5)i,x=4-4sqrt(5)i
Find the zeros of x^2-8x+96=0
The zeros of x^2-8x+96=0 are x=4+4sqrt(5)i,x=4-4sqrt(5)i