What are the solutions to the equation 4x^2+40x+100=0 ?

The solutions to the equation 4x^2+40x+100=0 are x=-5

Find the zeros of 4x^2+40x+100=0

The zeros of 4x^2+40x+100=0 are x=-5

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4 x^{2} + 40 x + 100 = 0

x = - 5

Solution steps

4 x^{2} + 40 x + 100 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 40 \pm 4 0 ^{2} - 4 \cdot 4 \cdot 100}{2 \cdot 4}

4 0^{2} - 4 \cdot 4 \cdot 100 = 0

x_{1, 2} = \frac{- 40 \pm 0}{2 \cdot 4}

x = \frac{- 40}{2 \cdot 4}

\frac{- 40}{2 \cdot 4} = - 5

x = - 5

The solution to the quadratic equation is:

x = - 5

x^{2} - 8 x + 96 = 0

x, 3 x^{2} - 5 y^{6} = 2 x

2 (3 x + 1)^{2} - 8 = 0

9 x^{2} - 18 x + 3 = 0

- x^{2} + 4 x - 96 = 0

What are the solutions to the equation 4x^2+40x+100=0 ?
The solutions to the equation 4x^2+40x+100=0 are x=-5
Find the zeros of 4x^2+40x+100=0
The zeros of 4x^2+40x+100=0 are x=-5