What are the solutions to the equation 2(5x+2)^2=64 ?

The solutions to the equation 2(5x+2)^2=64 are x=(4sqrt(2)-2)/5 ,x=(-4sqrt(2)-2)/5

Find the zeros of 2(5x+2)^2=64

The zeros of 2(5x+2)^2=64 are x=(4sqrt(2)-2)/5 ,x=(-4sqrt(2)-2)/5

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2 (5 x + 2)^{2} = 64

x = \frac{4 2 - 2}{5}, x = \frac{- 4 2 - 2}{5}

Decimal Notation

x = 0.73137 \dots, x = - 1.53137 \dots

Solution steps

2 (5 x + 2)^{2} = 64

Divide both sides by

2

(5 x + 2)^{2} = 32

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

5 x + 2 = 32 : x = \frac{4 2 - 2}{5}

Solve

5 x + 2 = - 32 : x = \frac{- 4 2 - 2}{5}

The solutions to the quadratic equation are:

x = \frac{4 2 - 2}{5}, x = \frac{- 4 2 - 2}{5}

x^{2} + 4 b = 0, b > 0

x^{2} - 7 x + \frac{5}{4} = 0

3 q^{2} - 105 q + 750 = 0

z^{2} - 7 z + 13 = 0

m x^{2} - 5 x + 2 = n x - 1

What are the solutions to the equation 2(5x+2)^2=64 ?
The solutions to the equation 2(5x+2)^2=64 are x=(4sqrt(2)-2)/5 ,x=(-4sqrt(2)-2)/5
Find the zeros of 2(5x+2)^2=64
The zeros of 2(5x+2)^2=64 are x=(4sqrt(2)-2)/5 ,x=(-4sqrt(2)-2)/5