What are the solutions to the equation (x+20)(x-5)=350 ?

The solutions to the equation (x+20)(x-5)=350 are x=15,x=-30

Find the zeros of (x+20)(x-5)=350

The zeros of (x+20)(x-5)=350 are x=15,x=-30

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(x + 20) (x - 5) = 350

x = 15, x = - 30

Solution steps

(x + 20) (x - 5) = 350

Expand

(x + 20) (x - 5) : x^{2} + 15 x - 100

x^{2} + 15 x - 100 = 350

Move

350

to the left side

x^{2} + 15 x - 450 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 1 \cdot ( - 450 )}{2 \cdot 1}

1 5^{2} - 4 \cdot 1 \cdot (- 450) = 45

x_{1, 2} = \frac{- 15 \pm 45}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 15 + 45}{2 \cdot 1}, x_{2} = \frac{- 15 - 45}{2 \cdot 1}

x = \frac{- 15 + 45}{2 \cdot 1} : 15

x = \frac{- 15 - 45}{2 \cdot 1} : - 30

The solutions to the quadratic equation are:

x = 15, x = - 30

q^{2} - 22 q + 120 = 0

(x - 1) (x - 2) = 2

x, c y^{2} = x^{2} + y

(2 - 3 x)^{2} = 0

5 x^{2} + 6 x = - 1

What are the solutions to the equation (x+20)(x-5)=350 ?
The solutions to the equation (x+20)(x-5)=350 are x=15,x=-30
Find the zeros of (x+20)(x-5)=350
The zeros of (x+20)(x-5)=350 are x=15,x=-30