What are the solutions to the equation (x-1)(x-2)=2 ?

The solutions to the equation (x-1)(x-2)=2 are x=3,x=0

Find the zeros of (x-1)(x-2)=2

The zeros of (x-1)(x-2)=2 are x=3,x=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x - 1) (x - 2) = 2

x = 3, x = 0

Solution steps

(x - 1) (x - 2) = 2

Expand

(x - 1) (x - 2) : x^{2} - 3 x + 2

x^{2} - 3 x + 2 = 2

Move

2

to the left side

x^{2} - 3 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot 0 = 3

x_{1, 2} = \frac{- ( - 3 ) \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 3}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 3}{2 \cdot 1}

x = \frac{- ( - 3 ) + 3}{2 \cdot 1} : 3

x = \frac{- ( - 3 ) - 3}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 3, x = 0

x, c y^{2} = x^{2} + y

(2 - 3 x)^{2} = 0

5 x^{2} + 6 x = - 1

(x + 9) (x - 2) = 60

x, ln (y) = A x^{2} + B

What are the solutions to the equation (x-1)(x-2)=2 ?
The solutions to the equation (x-1)(x-2)=2 are x=3,x=0
Find the zeros of (x-1)(x-2)=2
The zeros of (x-1)(x-2)=2 are x=3,x=0