What are the solutions to the equation 3(3x-1)^2=21 ?

The solutions to the equation 3(3x-1)^2=21 are x=(sqrt(7)+1)/3 ,x=(-sqrt(7)+1)/3

Find the zeros of 3(3x-1)^2=21

The zeros of 3(3x-1)^2=21 are x=(sqrt(7)+1)/3 ,x=(-sqrt(7)+1)/3

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3 (3 x - 1)^{2} = 21

x = \frac{7 + 1}{3}, x = \frac{- 7 + 1}{3}

Decimal Notation

x = 1.21525 \dots, x = - 0.54858 \dots

Solution steps

3 (3 x - 1)^{2} = 21

Divide both sides by

3

(3 x - 1)^{2} = 7

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x - 1 = 7 : x = \frac{7 + 1}{3}

Solve

3 x - 1 = - 7 : x = \frac{- 7 + 1}{3}

The solutions to the quadratic equation are:

x = \frac{7 + 1}{3}, x = \frac{- 7 + 1}{3}

(4 x - 1)^{2} = 196

2 x (4 x + 5) = - 3

5 x^{2} + 4 x + 7 = 0

x^{2} - 82 x + 1681 = 0

a x^{2} - 4 x + 6 = 0

What are the solutions to the equation 3(3x-1)^2=21 ?
The solutions to the equation 3(3x-1)^2=21 are x=(sqrt(7)+1)/3 ,x=(-sqrt(7)+1)/3
Find the zeros of 3(3x-1)^2=21
The zeros of 3(3x-1)^2=21 are x=(sqrt(7)+1)/3 ,x=(-sqrt(7)+1)/3