What are the solutions to the equation (4x-1)^2=196 ?

The solutions to the equation (4x-1)^2=196 are x= 15/4 ,x=-13/4

Find the zeros of (4x-1)^2=196

The zeros of (4x-1)^2=196 are x= 15/4 ,x=-13/4

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(4 x - 1)^{2} = 196

x = \frac{15}{4}, x = - \frac{13}{4}

Solution steps

(4 x - 1)^{2} = 196

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

4 x - 1 = 196 : x = \frac{15}{4}

Solve

4 x - 1 = - 196 : x = - \frac{13}{4}

The solutions to the quadratic equation are:

x = \frac{15}{4}, x = - \frac{13}{4}

2 x (4 x + 5) = - 3

5 x^{2} + 4 x + 7 = 0

x^{2} - 82 x + 1681 = 0

a x^{2} - 4 x + 6 = 0

x^{2} + 8 x + 4 = 6

What are the solutions to the equation (4x-1)^2=196 ?
The solutions to the equation (4x-1)^2=196 are x= 15/4 ,x=-13/4
Find the zeros of (4x-1)^2=196
The zeros of (4x-1)^2=196 are x= 15/4 ,x=-13/4