What are the solutions to the equation 5x^2+4x+7=0 ?

The solutions to the equation 5x^2+4x+7=0 are x=-2/5+i(sqrt(31))/5 ,x=-2/5-i(sqrt(31))/5

Find the zeros of 5x^2+4x+7=0

The zeros of 5x^2+4x+7=0 are x=-2/5+i(sqrt(31))/5 ,x=-2/5-i(sqrt(31))/5

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5 x^{2} + 4 x + 7 = 0

x = - \frac{2}{5} + i \frac{31}{5}, x = - \frac{2}{5} - i \frac{31}{5}

Solution steps

5 x^{2} + 4 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 5 \cdot 7}{2 \cdot 5}

Simplify

4^{2} - 4 \cdot 5 \cdot 7 : 231 i

x_{1, 2} = \frac{- 4 \pm 2 31 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 4 + 2 31 i}{2 \cdot 5}, x_{2} = \frac{- 4 - 2 31 i}{2 \cdot 5}

x = \frac{- 4 + 2 31 i}{2 \cdot 5} : - \frac{2}{5} + i \frac{31}{5}

x = \frac{- 4 - 2 31 i}{2 \cdot 5} : - \frac{2}{5} - i \frac{31}{5}

The solutions to the quadratic equation are:

x = - \frac{2}{5} + i \frac{31}{5}, x = - \frac{2}{5} - i \frac{31}{5}

x^{2} - 82 x + 1681 = 0

a x^{2} - 4 x + 6 = 0

x^{2} + 8 x + 4 = 6

x + 2 x^{2} - 4 = - 7 x + 6

(x - 1) (x + 3) = 6

What are the solutions to the equation 5x^2+4x+7=0 ?
The solutions to the equation 5x^2+4x+7=0 are x=-2/5+i(sqrt(31))/5 ,x=-2/5-i(sqrt(31))/5
Find the zeros of 5x^2+4x+7=0
The zeros of 5x^2+4x+7=0 are x=-2/5+i(sqrt(31))/5 ,x=-2/5-i(sqrt(31))/5