What are the solutions to the equation x^2+8x+4=6 ?

The solutions to the equation x^2+8x+4=6 are x=-4+3sqrt(2),x=-4-3sqrt(2)

Find the zeros of x^2+8x+4=6

The zeros of x^2+8x+4=6 are x=-4+3sqrt(2),x=-4-3sqrt(2)

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x^{2} + 8 x + 4 = 6

x = - 4 + 32, x = - 4 - 32

Decimal Notation

x = 0.24264 \dots, x = - 8.24264 \dots

Solution steps

x^{2} + 8 x + 4 = 6

Move

6

to the left side

x^{2} + 8 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 2) = 62

x_{1, 2} = \frac{- 8 \pm 6 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 6 2}{2 \cdot 1}, x_{2} = \frac{- 8 - 6 2}{2 \cdot 1}

x = \frac{- 8 + 6 2}{2 \cdot 1} : - 4 + 32

x = \frac{- 8 - 6 2}{2 \cdot 1} : - 4 - 32

The solutions to the quadratic equation are:

x = - 4 + 32, x = - 4 - 32

x + 2 x^{2} - 4 = - 7 x + 6

(x - 1) (x + 3) = 6

x + 2 = \frac{( x - 2 ) ^{2}}{2}

x, k x^{2} - 3 k x + 9 = 0

5 y^{2} - 2 = - 9 y

What are the solutions to the equation x^2+8x+4=6 ?
The solutions to the equation x^2+8x+4=6 are x=-4+3sqrt(2),x=-4-3sqrt(2)
Find the zeros of x^2+8x+4=6
The zeros of x^2+8x+4=6 are x=-4+3sqrt(2),x=-4-3sqrt(2)