What are the solutions to the equation (x-1)(x+3)=6 ?

The solutions to the equation (x-1)(x+3)=6 are x=-1+sqrt(10),x=-1-sqrt(10)

Find the zeros of (x-1)(x+3)=6

The zeros of (x-1)(x+3)=6 are x=-1+sqrt(10),x=-1-sqrt(10)

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(x - 1) (x + 3) = 6

x = - 1 + 10, x = - 1 - 10

Decimal Notation

x = 2.16227 \dots, x = - 4.16227 \dots

Solution steps

(x - 1) (x + 3) = 6

Expand

(x - 1) (x + 3) : x^{2} + 2 x - 3

x^{2} + 2 x - 3 = 6

Move

6

to the left side

x^{2} + 2 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 9 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 9) = 210

x_{1, 2} = \frac{- 2 \pm 2 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2 10}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 10}{2 \cdot 1}

x = \frac{- 2 + 2 10}{2 \cdot 1} : - 1 + 10

x = \frac{- 2 - 2 10}{2 \cdot 1} : - 1 - 10

The solutions to the quadratic equation are:

x = - 1 + 10, x = - 1 - 10

x + 2 = \frac{( x - 2 ) ^{2}}{2}

x, k x^{2} - 3 k x + 9 = 0

5 y^{2} - 2 = - 9 y

2 (3 x - 1)^{2} = 162

(x - 6)^{2} + 5 (x - 6) = 3 (x - 1)^{2}

What are the solutions to the equation (x-1)(x+3)=6 ?
The solutions to the equation (x-1)(x+3)=6 are x=-1+sqrt(10),x=-1-sqrt(10)
Find the zeros of (x-1)(x+3)=6
The zeros of (x-1)(x+3)=6 are x=-1+sqrt(10),x=-1-sqrt(10)