What are the solutions to the equation 5y^2-2=-9y ?

The solutions to the equation 5y^2-2=-9y are y= 1/5 ,y=-2

Find the zeros of 5y^2-2=-9y

The zeros of 5y^2-2=-9y are y= 1/5 ,y=-2

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5 y^{2} - 2 = - 9 y

y = \frac{1}{5}, y = - 2

Decimal Notation

y = 0.2, y = - 2

Solution steps

5 y^{2} - 2 = - 9 y

Move

9 y

to the left side

5 y^{2} - 2 + 9 y = 0

Write in the standard form

a x^{2} + b x + c = 0

5 y^{2} + 9 y - 2 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 5 ( - 2 )}{2 \cdot 5}

9^{2} - 4 \cdot 5 (- 2) = 11

y_{1, 2} = \frac{- 9 \pm 11}{2 \cdot 5}

Separate the solutions

y_{1} = \frac{- 9 + 11}{2 \cdot 5}, y_{2} = \frac{- 9 - 11}{2 \cdot 5}

y = \frac{- 9 + 11}{2 \cdot 5} : \frac{1}{5}

y = \frac{- 9 - 11}{2 \cdot 5} : - 2

The solutions to the quadratic equation are:

y = \frac{1}{5}, y = - 2

2 (3 x - 1)^{2} = 162

(x - 6)^{2} + 5 (x - 6) = 3 (x - 1)^{2}

x^{2} + 2 x + 1 = 5 x + 6

(x + 5) (x + 3) = 5 x + 25

9 x^{2} + 5 x + 10 = 0

What are the solutions to the equation 5y^2-2=-9y ?
The solutions to the equation 5y^2-2=-9y are y= 1/5 ,y=-2
Find the zeros of 5y^2-2=-9y
The zeros of 5y^2-2=-9y are y= 1/5 ,y=-2