What are the solutions to the equation 2(3x-1)^2=162 ?

The solutions to the equation 2(3x-1)^2=162 are x= 10/3 ,x=-8/3

Find the zeros of 2(3x-1)^2=162

The zeros of 2(3x-1)^2=162 are x= 10/3 ,x=-8/3

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2 (3 x - 1)^{2} = 162

x = \frac{10}{3}, x = - \frac{8}{3}

Decimal Notation

x = 3.33333 \dots, x = - 2.66666 \dots

Solution steps

2 (3 x - 1)^{2} = 162

Divide both sides by

2

(3 x - 1)^{2} = 81

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x - 1 = 81 : x = \frac{10}{3}

Solve

3 x - 1 = - 81 : x = - \frac{8}{3}

The solutions to the quadratic equation are:

x = \frac{10}{3}, x = - \frac{8}{3}

(x - 6)^{2} + 5 (x - 6) = 3 (x - 1)^{2}

x^{2} + 2 x + 1 = 5 x + 6

(x + 5) (x + 3) = 5 x + 25

9 x^{2} + 5 x + 10 = 0

(x + 6)^{2} = 12 x

What are the solutions to the equation 2(3x-1)^2=162 ?
The solutions to the equation 2(3x-1)^2=162 are x= 10/3 ,x=-8/3
Find the zeros of 2(3x-1)^2=162
The zeros of 2(3x-1)^2=162 are x= 10/3 ,x=-8/3