What are the solutions to the equation (x+5)(x+3)=5x+25 ?

The solutions to the equation (x+5)(x+3)=5x+25 are x=2,x=-5

Find the zeros of (x+5)(x+3)=5x+25

The zeros of (x+5)(x+3)=5x+25 are x=2,x=-5

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(x + 5) (x + 3) = 5 x + 25

x = 2, x = - 5

Solution steps

(x + 5) (x + 3) = 5 x + 25

Expand

(x + 5) (x + 3) : x^{2} + 8 x + 15

x^{2} + 8 x + 15 = 5 x + 25

Move

25

to the left side

x^{2} + 8 x - 10 = 5 x

Move

5 x

to the left side

x^{2} + 3 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 10) = 7

x_{1, 2} = \frac{- 3 \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 7}{2 \cdot 1}, x_{2} = \frac{- 3 - 7}{2 \cdot 1}

x = \frac{- 3 + 7}{2 \cdot 1} : 2

x = \frac{- 3 - 7}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = 2, x = - 5

9 x^{2} + 5 x + 10 = 0

(x + 6)^{2} = 12 x

(5 x + 4) (5 x - 4) = 0

9 (x - 1)^{2} + 7 = 0

x, x (1 - x) + m - h x = 0

What are the solutions to the equation (x+5)(x+3)=5x+25 ?
The solutions to the equation (x+5)(x+3)=5x+25 are x=2,x=-5
Find the zeros of (x+5)(x+3)=5x+25
The zeros of (x+5)(x+3)=5x+25 are x=2,x=-5