What are the solutions to the equation 9x^2+5x+10=0 ?

The solutions to the equation 9x^2+5x+10=0 are x=-5/18+i(sqrt(335))/(18),x=-5/18-i(sqrt(335))/(18)

Find the zeros of 9x^2+5x+10=0

The zeros of 9x^2+5x+10=0 are x=-5/18+i(sqrt(335))/(18),x=-5/18-i(sqrt(335))/(18)

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9 x^{2} + 5 x + 10 = 0

x = - \frac{5}{18} + i \frac{335}{18}, x = - \frac{5}{18} - i \frac{335}{18}

Solution steps

9 x^{2} + 5 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 9 \cdot 10}{2 \cdot 9}

Simplify

5^{2} - 4 \cdot 9 \cdot 10 : 335 i

x_{1, 2} = \frac{- 5 \pm 335 i}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 5 + 335 i}{2 \cdot 9}, x_{2} = \frac{- 5 - 335 i}{2 \cdot 9}

x = \frac{- 5 + 335 i}{2 \cdot 9} : - \frac{5}{18} + i \frac{335}{18}

x = \frac{- 5 - 335 i}{2 \cdot 9} : - \frac{5}{18} - i \frac{335}{18}

The solutions to the quadratic equation are:

x = - \frac{5}{18} + i \frac{335}{18}, x = - \frac{5}{18} - i \frac{335}{18}

(x + 6)^{2} = 12 x

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9 (x - 1)^{2} + 7 = 0

x, x (1 - x) + m - h x = 0

x, y = x^{2} - 8 x + 15

What are the solutions to the equation 9x^2+5x+10=0 ?
The solutions to the equation 9x^2+5x+10=0 are x=-5/18+i(sqrt(335))/(18),x=-5/18-i(sqrt(335))/(18)
Find the zeros of 9x^2+5x+10=0
The zeros of 9x^2+5x+10=0 are x=-5/18+i(sqrt(335))/(18),x=-5/18-i(sqrt(335))/(18)