What are the solutions to the equation 9(x-1)^2+7=0 ?

The solutions to the equation 9(x-1)^2+7=0 are x=1+i(sqrt(7))/3 ,x=1-i(sqrt(7))/3

Find the zeros of 9(x-1)^2+7=0

The zeros of 9(x-1)^2+7=0 are x=1+i(sqrt(7))/3 ,x=1-i(sqrt(7))/3

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9 (x - 1)^{2} + 7 = 0

x = 1 + i \frac{7}{3}, x = 1 - i \frac{7}{3}

Solution steps

9 (x - 1)^{2} + 7 = 0

Move

7

to the right side

9 (x - 1)^{2} = - 7

Divide both sides by

9

(x - 1)^{2} = - \frac{7}{9}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 1 = - \frac{7}{9} : x = 1 + i \frac{7}{3}

Solve

x - 1 = - - \frac{7}{9} : x = 1 - i \frac{7}{3}

The solutions to the quadratic equation are:

x = 1 + i \frac{7}{3}, x = 1 - i \frac{7}{3}

x, x (1 - x) + m - h x = 0

x, y = x^{2} - 8 x + 15

(3 x + 2) (3 x - 4) = 0

5 w^{2} - 2 w = 0

(4 x - 3)^{2} = 16

What are the solutions to the equation 9(x-1)^2+7=0 ?
The solutions to the equation 9(x-1)^2+7=0 are x=1+i(sqrt(7))/3 ,x=1-i(sqrt(7))/3
Find the zeros of 9(x-1)^2+7=0
The zeros of 9(x-1)^2+7=0 are x=1+i(sqrt(7))/3 ,x=1-i(sqrt(7))/3