What are the solutions to the equation solvefor x,y=x^2-8x+15 ?

The solutions to the equation solvefor x,y=x^2-8x+15 are x=4+sqrt(y+1),x=4-sqrt(y+1)

Find the zeros of solvefor x,y=x^2-8x+15

The zeros of solvefor x,y=x^2-8x+15 are x=4+sqrt(y+1),x=4-sqrt(y+1)

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solve for

x, y = x^{2} - 8 x + 15

x = 4 + y + 1, x = 4 - y + 1

Solution steps

y = x^{2} - 8 x + 15

Switch sides

x^{2} - 8 x + 15 = y

Move

y

to the left side

x^{2} - 8 x + 15 - y = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot ( 15 - y )}{2 \cdot 1}

Simplify

(- 8)^{2} - 4 \cdot 1 \cdot (15 - y) : 2 y + 1

x_{1, 2} = \frac{- ( - 8 ) \pm 2 y + 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 y + 1}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 2 y + 1}{2 \cdot 1}

x = \frac{- ( - 8 ) + 2 y + 1}{2 \cdot 1} : 4 + y + 1

x = \frac{- ( - 8 ) - 2 y + 1}{2 \cdot 1} : 4 - y + 1

The solutions to the quadratic equation are:

x = 4 + y + 1, x = 4 - y + 1

(3 x + 2) (3 x - 4) = 0

5 w^{2} - 2 w = 0

(4 x - 3)^{2} = 16

x^{2} - 14 x + 64 = 0

- x^{2} + 8 x + 5

What are the solutions to the equation solvefor x,y=x^2-8x+15 ?
The solutions to the equation solvefor x,y=x^2-8x+15 are x=4+sqrt(y+1),x=4-sqrt(y+1)
Find the zeros of solvefor x,y=x^2-8x+15
The zeros of solvefor x,y=x^2-8x+15 are x=4+sqrt(y+1),x=4-sqrt(y+1)