What are the solutions to the equation (3x+2)(3x-4)=0 ?

The solutions to the equation (3x+2)(3x-4)=0 are x=-2/3 ,x= 4/3

Find the zeros of (3x+2)(3x-4)=0

The zeros of (3x+2)(3x-4)=0 are x=-2/3 ,x= 4/3

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(3 x + 2) (3 x - 4) = 0

x = - \frac{2}{3}, x = \frac{4}{3}

Decimal Notation

x = - 0.66666 \dots, x = 1.33333 \dots

Solution steps

(3 x + 2) (3 x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x + 2 = 0 or 3 x - 4 = 0

Solve

3 x + 2 = 0 : x = - \frac{2}{3}

Solve

3 x - 4 = 0 : x = \frac{4}{3}

The solutions to the quadratic equation are:

x = - \frac{2}{3}, x = \frac{4}{3}

5 w^{2} - 2 w = 0

(4 x - 3)^{2} = 16

x^{2} - 14 x + 64 = 0

- x^{2} + 8 x + 5

x, m x^{2} + 2 x - 2 = 0

What are the solutions to the equation (3x+2)(3x-4)=0 ?
The solutions to the equation (3x+2)(3x-4)=0 are x=-2/3 ,x= 4/3
Find the zeros of (3x+2)(3x-4)=0
The zeros of (3x+2)(3x-4)=0 are x=-2/3 ,x= 4/3