What are the solutions to the equation 5w^2-2w=0 ?

The solutions to the equation 5w^2-2w=0 are w= 2/5 ,w=0

Find the zeros of 5w^2-2w=0

The zeros of 5w^2-2w=0 are w= 2/5 ,w=0

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5 w^{2} - 2 w = 0

w = \frac{2}{5}, w = 0

Solution steps

5 w^{2} - 2 w = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 5 \cdot 0}{2 \cdot 5}

(- 2)^{2} - 4 \cdot 5 \cdot 0 = 2

w_{1, 2} = \frac{- ( - 2 ) \pm 2}{2 \cdot 5}

Separate the solutions

w_{1} = \frac{- ( - 2 ) + 2}{2 \cdot 5}, w_{2} = \frac{- ( - 2 ) - 2}{2 \cdot 5}

w = \frac{- ( - 2 ) + 2}{2 \cdot 5} : \frac{2}{5}

w = \frac{- ( - 2 ) - 2}{2 \cdot 5} : 0

The solutions to the quadratic equation are:

w = \frac{2}{5}, w = 0

(4 x - 3)^{2} = 16

x^{2} - 14 x + 64 = 0

- x^{2} + 8 x + 5

x, m x^{2} + 2 x - 2 = 0

2 (x - 5)^{2} = 17

What are the solutions to the equation 5w^2-2w=0 ?
The solutions to the equation 5w^2-2w=0 are w= 2/5 ,w=0
Find the zeros of 5w^2-2w=0
The zeros of 5w^2-2w=0 are w= 2/5 ,w=0