What are the solutions to the equation x^2+82x+1681=0 ?

The solutions to the equation x^2+82x+1681=0 are x=-41

Find the zeros of x^2+82x+1681=0

The zeros of x^2+82x+1681=0 are x=-41

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x^{2} + 82 x + 1681 = 0

x = - 41

Solution steps

x^{2} + 82 x + 1681 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 82 \pm 8 2 ^{2} - 4 \cdot 1 \cdot 1681}{2 \cdot 1}

8 2^{2} - 4 \cdot 1 \cdot 1681 = 0

x_{1, 2} = \frac{- 82 \pm 0}{2 \cdot 1}

x = \frac{- 82}{2 \cdot 1}

\frac{- 82}{2 \cdot 1} = - 41

x = - 41

The solution to the quadratic equation is:

x = - 41

x^{2} + 5 x + 2 = - 4

- x^{2} - 5 x + 25 = - 2 x^{2} + 5 x

16 x^{2} - 24 x + 7 = 0

(w - 8) (w + 5) = 14

6 x^{2} - 8 x + 1

What are the solutions to the equation x^2+82x+1681=0 ?
The solutions to the equation x^2+82x+1681=0 are x=-41
Find the zeros of x^2+82x+1681=0
The zeros of x^2+82x+1681=0 are x=-41