What are the solutions to the equation n^2+10=7n ?

The solutions to the equation n^2+10=7n are n=5,n=2

Find the zeros of n^2+10=7n

The zeros of n^2+10=7n are n=5,n=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

n^{2} + 10 = 7 n

n = 5, n = 2

Solution steps

n^{2} + 10 = 7 n

Move

7 n

to the left side

n^{2} + 10 - 7 n = 0

Write in the standard form

a x^{2} + b x + c = 0

n^{2} - 7 n + 10 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot 10 = 3

n_{1, 2} = \frac{- ( - 7 ) \pm 3}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- ( - 7 ) + 3}{2 \cdot 1}, n_{2} = \frac{- ( - 7 ) - 3}{2 \cdot 1}

n = \frac{- ( - 7 ) + 3}{2 \cdot 1} : 5

n = \frac{- ( - 7 ) - 3}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

n = 5, n = 2

2 x^{2} - 6 x + c = 0

15 a x^{2} + 6 x - 3 a x = 0

x^{2} - 3 x - 8 = x + 4

3 x (1 - 2 x) = 16

5 x^{2} - 2 = - 9 x

What are the solutions to the equation n^2+10=7n ?
The solutions to the equation n^2+10=7n are n=5,n=2
Find the zeros of n^2+10=7n
The zeros of n^2+10=7n are n=5,n=2