What are the solutions to the equation 2x^2-6x+c=0 ?

The solutions to the equation 2x^2-6x+c=0 are x=(3+sqrt(-2c+9))/2 ,x=(3-sqrt(-2c+9))/2

Find the zeros of 2x^2-6x+c=0

The zeros of 2x^2-6x+c=0 are x=(3+sqrt(-2c+9))/2 ,x=(3-sqrt(-2c+9))/2

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2 x^{2} - 6 x + c = 0

x = \frac{3 + - 2 c + 9}{2}, x = \frac{3 - - 2 c + 9}{2}

Solution steps

2 x^{2} - 6 x + c = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 2 c}{2 \cdot 2}

Simplify

(- 6)^{2} - 4 \cdot 2 c : 2 9 - 2 c

x_{1, 2} = \frac{- ( - 6 ) \pm 2 9 - 2 c}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 9 - 2 c}{2 \cdot 2}, x_{2} = \frac{- ( - 6 ) - 2 9 - 2 c}{2 \cdot 2}

x = \frac{- ( - 6 ) + 2 9 - 2 c}{2 \cdot 2} : \frac{3 + - 2 c + 9}{2}

x = \frac{- ( - 6 ) - 2 9 - 2 c}{2 \cdot 2} : \frac{3 - - 2 c + 9}{2}

The solutions to the quadratic equation are:

x = \frac{3 + - 2 c + 9}{2}, x = \frac{3 - - 2 c + 9}{2}

15 a x^{2} + 6 x - 3 a x = 0

x^{2} - 3 x - 8 = x + 4

3 x (1 - 2 x) = 16

5 x^{2} - 2 = - 9 x

x^{2} + 70 = 17 x

What are the solutions to the equation 2x^2-6x+c=0 ?
The solutions to the equation 2x^2-6x+c=0 are x=(3+sqrt(-2c+9))/2 ,x=(3-sqrt(-2c+9))/2
Find the zeros of 2x^2-6x+c=0
The zeros of 2x^2-6x+c=0 are x=(3+sqrt(-2c+9))/2 ,x=(3-sqrt(-2c+9))/2