What are the solutions to the equation (x-6)(x+6)-(x-3)2=0 ?

The solutions to the equation (x-6)(x+6)-(x-3)2=0 are x=1+sqrt(31),x=1-sqrt(31)

Find the zeros of (x-6)(x+6)-(x-3)2=0

The zeros of (x-6)(x+6)-(x-3)2=0 are x=1+sqrt(31),x=1-sqrt(31)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x - 6) (x + 6) - (x - 3) 2 = 0

x = 1 + 31, x = 1 - 31

Solution steps

(x - 6) (x + 6) - (x - 3) \cdot 2 = 0

Expand

(x - 6) (x + 6) - (x - 3) \cdot 2 : x^{2} - 2 x - 30

x^{2} - 2 x - 30 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 30 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 30) = 231

x_{1, 2} = \frac{- ( - 2 ) \pm 2 31}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 31}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 31}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 31}{2 \cdot 1} : 1 + 31

x = \frac{- ( - 2 ) - 2 31}{2 \cdot 1} : 1 - 31

The solutions to the quadratic equation are:

x = 1 + 31, x = 1 - 31

0.2 x^{2} - 0.5 x - 7 = 0

13 x - 36 = x^{2}

x, 2 x^{2} + y^{2} = C

4 x^{2} + 3 x + 22 = 0

x^{2} - a x - 2 a = 0

What are the solutions to the equation (x-6)(x+6)-(x-3)2=0 ?
The solutions to the equation (x-6)(x+6)-(x-3)2=0 are x=1+sqrt(31),x=1-sqrt(31)
Find the zeros of (x-6)(x+6)-(x-3)2=0
The zeros of (x-6)(x+6)-(x-3)2=0 are x=1+sqrt(31),x=1-sqrt(31)