What are the solutions to the equation x^2-ax-2a=0 ?

The solutions to the equation x^2-ax-2a=0 are x=(a+sqrt(a^2+8a))/2 ,x=(a-sqrt(a^2+8a))/2

Find the zeros of x^2-ax-2a=0

The zeros of x^2-ax-2a=0 are x=(a+sqrt(a^2+8a))/2 ,x=(a-sqrt(a^2+8a))/2

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x^{2} - a x - 2 a = 0

x = \frac{a + a ^{2} + 8 a}{2}, x = \frac{a - a ^{2} + 8 a}{2}

Solution steps

x^{2} - a x - 2 a = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - a ) \pm ( - a ) ^{2} - 4 \cdot 1 \cdot ( - 2 a )}{2 \cdot 1}

Simplify

(- a)^{2} - 4 \cdot 1 \cdot (- 2 a) : a^{2} + 8 a

x_{1, 2} = \frac{- ( - a ) \pm a ^{2} + 8 a}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - a ) + a ^{2} + 8 a}{2 \cdot 1}, x_{2} = \frac{- ( - a ) - a ^{2} + 8 a}{2 \cdot 1}

x = \frac{- ( - a ) + a ^{2} + 8 a}{2 \cdot 1} : \frac{a + a ^{2} + 8 a}{2}

x = \frac{- ( - a ) - a ^{2} + 8 a}{2 \cdot 1} : \frac{a - a ^{2} + 8 a}{2}

The solutions to the quadratic equation are:

x = \frac{a + a ^{2} + 8 a}{2}, x = \frac{a - a ^{2} + 8 a}{2}

x^{2} - 25 x + 475 = 0

x^{2} + 3^{3} = 31

(11 x + 13)^{2} - 4 (11 x + 13) - 21 = 0

(5 - x) (2 x + 3) = 0

3 x^{2} - 132 = 0

What are the solutions to the equation x^2-ax-2a=0 ?
The solutions to the equation x^2-ax-2a=0 are x=(a+sqrt(a^2+8a))/2 ,x=(a-sqrt(a^2+8a))/2
Find the zeros of x^2-ax-2a=0
The zeros of x^2-ax-2a=0 are x=(a+sqrt(a^2+8a))/2 ,x=(a-sqrt(a^2+8a))/2